How do you solve the equation 3x + 5 = 20?

How do you solve the equation 3x + 5 = 20?

• A. x = 3
• B. x = 5
• C. x = 10
• D. x = 15

Answer: (B)

To solve the equation \(3x + 5 = 20\), you start by isolating the variable \(x\). This is accomplished through a series of logical steps. First, subtract 5 from both sides of the equation to eliminate the constant on the left-hand side: \[ 3x + 5 - 5 = 20 - 5 \] This simplifies to: \[ 3x = 15 \] Next, to solve for \(x\), divide both sides of the equation by 3: \[ \frac{3x}{3} = \frac{15}{3} \] Which results in: \[ x = 5 \] Thus, the solution to the equation \(3x + 5 = 20\) is \(x = 5\). This confirms that the answer provided aligns with the correct computations and reasoning leading to the isolation of \(x\).

To solve the equation (3x + 5 = 20), you start by isolating the variable (x). This is accomplished through a series of logical steps.

First, subtract 5 from both sides of the equation to eliminate the constant on the left-hand side:

[

3x + 5 - 5 = 20 - 5

]

This simplifies to:

[

3x = 15

]

Next, to solve for (x), divide both sides of the equation by 3:

[

\frac{3x}{3} = \frac{15}{3}

]

Which results in:

[

x = 5

]

Thus, the solution to the equation (3x + 5 = 20) is (x = 5). This confirms that the answer provided aligns with the correct computations and reasoning leading to the isolation of (x).